Fix #13514: Set selectedIndex to -1 when non-matching value is set on a select. Close gh-1191.

This commit is contained in:
ruado1987 2013-03-03 23:51:04 +08:00 committed by Richard Gibson
parent ab5b0ff3f3
commit 48d71d0c3e
2 changed files with 30 additions and 7 deletions

View File

@ -275,13 +275,20 @@ jQuery.extend({
},
set: function( elem, value ) {
var values = jQuery.makeArray( value );
jQuery(elem).find("option").each(function() {
this.selected = jQuery.inArray( jQuery(this).val(), values ) >= 0;
});
if ( !values.length ) {
var optionSet, option,
options = elem.options,
values = jQuery.makeArray( value ),
i = options.length;
while ( i-- ) {
option = options[ i ];
if ( (option.selected = jQuery.inArray( jQuery(option).val(), values ) >= 0) ) {
optionSet = true;
}
}
// force browsers to behave consistently when non-matching value is set
if ( !optionSet ) {
elem.selectedIndex = -1;
}
return values;

View File

@ -850,6 +850,22 @@ test( "val()", function() {
equal( jQuery("<option/>").val("test").attr("value"), "test", "Setting value sets the value attribute" );
});
test("val() with non-matching values on dropdown list", function() {
expect( 3 );
jQuery("#select5").val( "" );
equal( jQuery("#select5").val(), null, "Non-matching set on select-one" );
var select6 = jQuery("<select multiple id=\"select6\"><option value=\"1\">A</option><option value=\"2\">B</option></select>").appendTo("#form");
jQuery(select6).val( "nothing" );
equal( jQuery(select6).val(), null, "Non-matching set (single value) on select-multiple" );
jQuery(select6).val( ["nothing1", "nothing2"] );
equal( jQuery(select6).val(), null, "Non-matching set (array of values) on select-multiple" );
select6.remove();
});
if ( "value" in document.createElement("meter") &&
"value" in document.createElement("progress") ) {