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Fix #13514: Set selectedIndex to -1 when non-matching value is set on a select. Close gh-1191.
(cherry picked from commit 48d71d0c3e
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@ -272,13 +272,20 @@ jQuery.extend({
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},
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set: function( elem, value ) {
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var values = jQuery.makeArray( value );
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jQuery(elem).find("option").each(function() {
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this.selected = jQuery.inArray( jQuery(this).val(), values ) >= 0;
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});
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if ( !values.length ) {
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var optionSet, option,
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options = elem.options,
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values = jQuery.makeArray( value ),
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i = options.length;
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while ( i-- ) {
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option = options[ i ];
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if ( (option.selected = jQuery.inArray( jQuery(option).val(), values ) >= 0) ) {
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optionSet = true;
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}
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}
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// force browsers to behave consistently when non-matching value is set
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if ( !optionSet ) {
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elem.selectedIndex = -1;
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}
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return values;
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@ -846,6 +846,22 @@ test( "val()", function() {
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equal( jQuery("<option/>").val("test").attr("value"), "test", "Setting value sets the value attribute" );
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});
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test("val() with non-matching values on dropdown list", function() {
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expect( 3 );
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jQuery("#select5").val( "" );
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equal( jQuery("#select5").val(), null, "Non-matching set on select-one" );
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var select6 = jQuery("<select multiple id=\"select6\"><option value=\"1\">A</option><option value=\"2\">B</option></select>").appendTo("#form");
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jQuery(select6).val( "nothing" );
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equal( jQuery(select6).val(), null, "Non-matching set (single value) on select-multiple" );
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jQuery(select6).val( ["nothing1", "nothing2"] );
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equal( jQuery(select6).val(), null, "Non-matching set (array of values) on select-multiple" );
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select6.remove();
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});
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if ( "value" in document.createElement("meter") &&
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"value" in document.createElement("progress") ) {
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